• Kerbal Space Program Delta V Map
• Kerbal Space Program Cheat Engine
• Cheat Sheet For Chemical Equilibrium
• Ksp Dv Cheat Sheet
• Ksp Keyboard Cheat Sheet
• KSP 1.2 Debug/Cheat Menu - Technical Support (PC, Modded ..

Kerbal Space Program rocket scientist's cheat sheet: Delta-v maps, equations and more for your reference so you can get from here to there and back again.

Jan 25, 2018 - Gr. 12 Chemical Systems and Equilibrium Cheat Sheet. Ksp (Solubility product constant): the product of the conc of ions in a saturated. With the release of KSP 0.90.0, 'Beta Than Ever', Kerbals have specific skill sets such as Pilot, Scientist, and Engineer. 334 votes, 39 comments. 1.2m members in the KerbalSpaceProgram community. The Kerbal Space Program subreddit. For all your gaming related, space. KSP Controls Author: Richard Jones Created Date: 4/10/2013 5:40:57 AM. Credit for the center image: u/gmiezis from his high-res loading screen for KSP. If anyone is interested I can upload the.psd file so the action groups can be edited. Edit: wow thanks for all the support everyone. I will post the psd when I get home from work. And thanks for pointing out incorrect info. I will verify and fix once I have time. A collection of helpful cheat sheets for the game Kerbal Space Program by SQUAD - Kowgan/kspcheatsheets.

• 1Mathematics
  • 1.3Delta-v (Δv)
• 2Math examples

Mathematics

Thrust-to-weight ratio (TWR)

→ See also: Thrust-to-weight ratio

This is Newton's Second Law. If the ratio is less than 1 the craft will not lift off the ground. Note that the local gravitational acceleration, which is usually the surface gravity of the body the rocket is starting from, is required.

• ${\displaystyle F_T}$ is the thrust of the engines
• ${\displaystyle m}$ the total mass of the craft
• ${\displaystyle g}$ the local gravitational acceleration (usually surface gravity)

Combined specific impulse (I_sp)

→ See also: Specific impulse

If the I_sp is the same for all engines in a stage, then the I_sp is equal to a single engine. If the I_sp is different for engines in a single stage, then use the following equation:

${\displaystyle I_{sp}=\frac{(F_1+F_2+\dots )}{\frac{F_1}{I_{sp1}}+\frac{F_2}{I_{sp2}}+\dots }}$

Delta-v (Δv)

Basic calculation

→ See also: Tutorial:Advanced Rocket Design

Basic calculation of a rocket's Δv. Use the atmospheric and vacuum thrust values for atmospheric and vacuum Δv, respectively.

• ${\displaystyle \mathrm{\Delta }v}$ is the velocity change possible in m/s
• ${\displaystyle M_{start}}$ is the starting mass in the same unit as ${\displaystyle M_{end}}$
• ${\displaystyle M_{end}}$ is the end mass in the same unit as ${\displaystyle M_{start}}$
• ${\displaystyle I_{sp}}$ is the specific impulse of the engine in seconds

True Δv of a stage that crosses from atmosphere to vacuum

Calculation of a rocket stage's Δv, taking into account transitioning from atmosphere to vacuum. Δv_out is the amount of Δv required to leave a body's atmosphere, not reach orbit. This equation is useful to figure out the actual Δv of a stage that transitions from atmosphere to vacuum.

${\displaystyle \mathrm{\Delta }{v}_T=\frac{\mathrm{\Delta }{v}_{atm}-\mathrm{\Delta }{v}_{out}}{\mathrm{\Delta }{v}_{atm}}\cdot \mathrm{\Delta }{v}_{vac}+\mathrm{\Delta }{v}_{out}}$

Maps

Various fan-made maps showing the Δv required to travel to a certain body.

Subway style Δv map (KSP 1.2.1):

Total Δv values

Δv change values

Δv with Phase Angles

Precise Total Δv values

WAC's Δv Map for KSP 1.0.4

Maximum Δv chart

This chart is a quick guide to what engine to use for a single stage interplanetary ship. No matter how much fuel you add you will never reach these ΔV without staging to shed mass or using the slingshot maneuver. (These calculations use a full/empty fuel-tank mass ratio of 9 for all engines except those noted.)

(Version: 1.6.1)

Math examples

TWR

• Copy template:

TWR = F / (m * g) > 1

I_sp

1. When I_sp is the same for all engines in a stage, then the I_sp is equal to a single engine. So six 200 I_sp engines still yields only 200 I_sp.
2. When I_sp is different for engines in a single stage, then use the following equation:

Kerbal Space Program Delta V Map

• Equation:

${\displaystyle I_{sp}=\frac{(F_1+F_2+\dots )}{\frac{F_1}{I_{sp1}}+\frac{F_2}{I_{sp2}}+\dots }}$

• Simplified:

I_sp = ( F1 + F2 + .. ) / ( ( F1 / I_sp1 ) + ( F2 / I_sp2 ) + .. )

• Explained:

I_sp = ( Force of thrust of 1st engine + Force of thrust of 2nd engine..and so on.. ) / ( ( Force of thrust of 1st engine / I_sp of 1st engine ) + ( Force of thrust of 2nd engine / I_sp of 2nd engine ) + ..and so on.. )

• Example:

Two engines, one rated 200 newtons and 120 seconds I_sp ; another engine rated 50 newtons and 200 seconds I_sp.

Isp = (200 newtons + 50 newtons) / ( ( 200 newtons / 120 ) + ( 50 newtons / 200 ) = 130.4347826 seconds I_sp

Δv

1. For atmospheric Δv value, use atmospheric ${\displaystyle I_{sp}}$ values.
2. For vacuum Δv value, use vacuum ${\displaystyle I_{sp}}$ values.
3. Use this equation to figure out the Δv per stage:

• Equation:

${\displaystyle \mathrm{\Delta }v=ln\left(\frac{M_{start}}{M_{dry}}\right)\cdot I_{sp}\cdot 9.81\frac{m}{s^2}}$

• Simplified:

Δv = ln ( Mstart / Mdry ) * I_sp * g

• Explained:

Δv = ln ( starting mass / dry mass ) X Isp X 9.81

• Example:

Single stage rocket that weighs 23 tons when full, 15 tons when fuel is emptied, and engine that outputs 120 seconds I_sp.

Δv = ln ( 23 Tons / 15 Tons ) × 120 seconds I_sp × 9.81m/s² = Total Δv of 503.0152618 m/s

Maximum Δv

Simplified version of the Δv calculation to find the maximum Δv a craft with the given ISP could hope to achieve. This is done by using a magic 0 mass engine and not having a payload.

• Equation:

${\displaystyle \mathrm{\Delta }v=21.576745349086\cdot I_{sp}}$

• Simplified:

Δv =21.576745349086 * I_sp

• Explained / Examples:

This calculation only uses the mass of the fuel tanks and so the ln ( Mstart / Mdry ) part of the Δv equation has been replaced by a constant as Mstart / Mdry is always 9 (or worse with some fuel tanks) regardless of how many fuel tanks you use.

The following example will use a single stage and fuel tanks in the T-100 to Jumbo 64 range with an engine that outputs 380 seconds I_sp.

Δv = ln ( 18 Tons / 2 Tons ) × 380 seconds I_sp × 9.81m/s² = Maximum Δv of 8199.1632327878 m/s

Δv = 2.1972245773 × 380 seconds I_sp × 9.82m/s² = Maximum Δv of 8199.1632327878 m/s (Replaced the log of mass with a constant as the ratio of total mass to dry mass is constant regardless of the number of tanks used as there is no other mass involved)

Δv = 21.576745349086 × 380 seconds I_sp = Maximum Δv of 8199.1632327878 m/s (Reduced to its most simple form by combining all the constants)

True Δv

1. How to calculate the Δv of a rocket stage that transitions from Kerbin atmosphere to vacuum.
2. Assumption: It takes roughly 2500 m/s of Δv to escape Kerbin's atmosphere before vacuum Δv values take over for the stage powering the transition (actual value ranges between 2000 m/s and 3400 m/s depending on ascent). Note that, as of KSP 1.3.1, around 3800 m/s of Δv is required to reach an 80km orbit from the KSC.
3. Note: This equation is a guess, an approximation, and is not 100% accurate. Per forum user stupid_chris who came up with the equation: 'The results will vary a bit depending on your TWR and such, but it should usually be pretty darn accurate.'

• Equation for Kerbin atmospheric escape:

${\displaystyle \mathrm{\Delta }{v}_T=\frac{\mathrm{\Delta }{v}_{atm}-\mathrm{\Delta }{v}_{out}}{\mathrm{\Delta }{v}_{atm}}\cdot \mathrm{\Delta }{v}_{vac}+\mathrm{\Delta }{v}_{out}}$

• Simplified:

True Δv = ( ( Δv atm - 2500 ) / Δv atm ) * Δv vac + 2500

• Explained:

True Δv = ( ( Total Δv in atmosphere - 2500 m/s) / Total Δv in atmosphere ) X Total Δv in vacuum + 2500

• Example:

Single stage with total atmospheric Δv of 5000 m/s, and rated 6000 Δv in vacuum.

Transitional Δv = ( ( 5000 Δv atm - 2500 Δv required to escape Kerbin atmosphere ) / 5000 Δv atm ) X 6000 Δv vac + 2500 Δv required to escape Kerbin atmosphere = Total Δv of 5500 m/s

See also

Kerbal Space Program Raketentechnikers cheat sheet: Delta-v maps, Gleichungen und mehr als Vorlagen, um immer wieder darauf zurückgreifen zu können.

• 1Mathematik
  • 1.3Delta-v (Δv)
• 2Mathematische Beispiele

Mathematik

Schub-Gewichtsverhältnis (TWR)

Template:Siehe auchDas ist Newtons zweites Gesetz. Die Rakete verlässt den Boden nicht, wenn das Verhältnis weniger als 1 ist. Beachte dass die lokale Fallbeschleunigung, welche normalerweise die Anziehungskraft des Körper auf dem die Rakete start ist, benötigt wird.

Kombination spezifischer Impulse(I_sp)

Template:Siehe auchWenn I_sp für alle Antriebe in einer Stufe gleich ist, dann ist I_sp gleich zu einem einzelnen Antrieb. Wenn I_sp unterschiedlich für Antriebe in einer Stufe ist, dann gilt folgende Gleichung:

2002 mercury 75 hp 2 stroke manual. ${\displaystyle I_{sp}=\frac{(F_1+F_2+\dots )}{\frac{F_1}{I_{sp1}}+\frac{F_2}{I_{sp2}}+\dots }}$

Delta-v (Δv)

Einfache Berechnung

Template:Siehe auchBenutze für die einfach Berechnung von Δv die Werte für den atmosphärischen- und Vakuumantrieb, für die Δv Werte der Atmosphere und des Vakuums.

Wahre Δv Wert eines Antriebs der von der Atmosphäre zum Vakuum übergeht

Die Berechnung von Δv in einer Raketenstufe, bei Berücksichtigung des Übergans von Atmosphäre zu Vakuum. Δv_out ist die Menge an Δv benötigt um die Atmosphäre eines Planetens zu verlassen, nicht um die Umlaufbahn zu erreichen. Diese Gleichung ist sinnvoll um den tatsächlichen Wert von Δv einer Stufe, die von der Atmospähre ins Vakuum übergeht herauszufinden.

${\displaystyle \mathrm{\Delta }{v}_T=\frac{\mathrm{\Delta }{v}_{atm}-\mathrm{\Delta }{v}_{out}}{\mathrm{\Delta }{v}_{atm}}\cdot \mathrm{\Delta }{v}_{vac}+\mathrm{\Delta }{v}_{out}}$

Maps

Verschiedene englischsprachige Maps die den benötigten Wert von Δv angeben, um einen bestimmten Planeten zu erreichen.

Kerbal Space Program Cheat Engine

U-Bahn ähnliche Δv map (KSP 1.2.1):

Ganze Δv Werte

Δv Änderungswerte

Δv mit Phasen Winkel

Genaue ganze Δv Werte

WAC's Δv Map für KSP 1.0.4

Maximales Δv Tabelle

Cheat Sheet For Chemical Equilibrium

Diese Tabelle ist eine kurze Guide, die zeigt welchen Antrieb man für ein Interplanetaren Schiff, mit einer einzelnen Stufe, benutzen soll. Egal wie viel Treibstoff man benutzt, man wird nie diese ΔV Werte erreichen ohne Abstufungen um Masse zu verlieren oder das Slingshot Manöver zu verwenden. (Diese Berechnungen verwenden ein Voll-zu-Leerer Treibstofftank Massenverhältnis von 9 für alle Antriebe, außer die erwähnten.)

(Version: 1.6.1)

Mathematische Beispiele

TWR

• Vorlage zum kopieren:

TWR = F / (m * g) > 1

I_sp

1. Wenn I_sp für alle Antriebe in einer Stufe gleich ist, I_sp ist das selbe wie von einem einzigen Antrieb. Sechs 200 I_sp Antriebe bringen also weiterhin 200 I_sp.
2. Wenn I_sp unterschiedlich ist für die Antriebe einer einzelnen Stufe, benutzte folgende Gleichung:

• Gleichung:

${\displaystyle I_{sp}=\frac{(F_1+F_2+\dots )}{\frac{F_1}{I_{sp1}}+\frac{F_2}{I_{sp2}}+\dots }}$

• Vereinfacht:

I_sp = ( F1 + F2 + .. ) / ( ( F1 / I_sp1 ) + ( F2 / I_sp2 ) + .. )

• Erklärt:

I_sp = (Antriebskraft des ersten Antriebs, Antriebskraft des zweiten Antriebs, und so weiter.. ) / ( ( Force of thrust of 1st engine / I_sp of 1st engine ) + ( Force of thrust of 2nd engine / I_sp of 2nd engine ) + ..and so on.. )

• Example:

Two engines, one rated 200 newtons and 120 seconds I_sp ; another engine rated 50 newtons and 200 seconds I_sp.

Isp = (200 newtons + 50 newtons) / ( ( 200 newtons / 120 ) + ( 50 newtons / 200 ) = 130.4347826 seconds I_sp

Δv

1. For atmospheric Δv value, use atmospheric ${\displaystyle I_{sp}}$ values.
2. For vacuum Δv value, use vacuum ${\displaystyle I_{sp}}$ values.
3. Use this equation to figure out the Δv per stage:

• Equation:

${\displaystyle \mathrm{\Delta }v=ln\left(\frac{M_{start}}{M_{dry}}\right)\cdot I_{sp}\cdot 9.81\frac{m}{s^2}}$

• Simplified:

Δv = ln ( Mstart / Mdry ) * I_sp * g

• Explained:

Δv = ln ( starting mass / dry mass ) X Isp X 9.81

• Example:

Single stage rocket that weighs 23 tons when full, 15 tons when fuel is emptied, and engine that outputs 120 seconds I_sp.

Δv = ln ( 23 Tons / 15 Tons ) × 120 seconds I_sp × 9.81m/s² = Total Δv of 503.0152618 m/s

Maximum Δv

Simplified version of the Δv calculation to find the maximum Δv a craft with the given ISP could hope to achieve. This is done by using a magic 0 mass engine and not having a payload.

• Equation:

${\displaystyle \mathrm{\Delta }v=21.576745349086\cdot I_{sp}}$

Ksp Dv Cheat Sheet

• Simplified:

Δv =21.576745349086 * I_sp

• Explained / Examples:

This calculation only uses the mass of the fuel tanks and so the ln ( Mstart / Mdry ) part of the Δv equation has been replaced by a constant as Mstart / Mdry is always 9 (or worse with some fuel tanks) regardless of how many fuel tanks you use.

The following example will use a single stage and fuel tanks in the T-100 to Jumbo 64 range with an engine that outputs 380 seconds I_sp.

Δv = ln ( 18 Tons / 2 Tons ) × 380 seconds I_sp × 9.81m/s² = Maximum Δv of 8199.1632327878 m/s

Δv = 2.1972245773 × 380 seconds I_sp × 9.82m/s² = Maximum Δv of 8199.1632327878 m/s (Replaced the log of mass with a constant as the ratio of total mass to dry mass is constant regardless of the number of tanks used as there is no other mass involved)

Δv = 21.576745349086 × 380 seconds I_sp = Maximum Δv of 8199.1632327878 m/s (Reduced to its most simple form by combining all the constants)

True Δv

1. How to calculate the Δv of a rocket stage that transitions from Kerbin atmosphere to vacuum.
2. Assumption: It takes roughly 2500 m/s of Δv to escape Kerbin's atmosphere before vacuum Δv values take over for the stage powering the transition (actual value ranges between 2000 m/s and 3400 m/s depending on ascent). Note that, as of KSP 1.3.1, around 3800 m/s of Δv is required to reach an 80km orbit from the KSC.
3. Note: This equation is a guess, an approximation, and is not 100% accurate. Per forum user stupid_chris who came up with the equation: 'The results will vary a bit depending on your TWR and such, but it should usually be pretty darn accurate.'

• Equation for Kerbin atmospheric escape:

${\displaystyle \mathrm{\Delta }{v}_T=\frac{\mathrm{\Delta }{v}_{atm}-\mathrm{\Delta }{v}_{out}}{\mathrm{\Delta }{v}_{atm}}\cdot \mathrm{\Delta }{v}_{vac}+\mathrm{\Delta }{v}_{out}}$

• Simplified:

True Δv = ( ( Δv atm - 2500 ) / Δv atm ) * Δv vac + 2500

• Explained:

True Δv = ( ( Total Δv in atmosphere - 2500 m/s) / Total Δv in atmosphere ) X Total Δv in vacuum + 2500

• Example:

Single stage with total atmospheric Δv of 5000 m/s, and rated 6000 Δv in vacuum.

Transitional Δv = ( ( 5000 Δv atm - 2500 Δv required to escape Kerbin atmosphere ) / 5000 Δv atm ) X 6000 Δv vac + 2500 Δv required to escape Kerbin atmosphere = Total Δv of 5500 m/s

Ksp Keyboard Cheat Sheet

See also

KSP 1.2 Debug/Cheat Menu - Technical Support (PC, Modded ..